(5x-10)+(3x^2-12)=180

Solution for (5x-10)+(3x^2-12)=180 equation:

(5x-10)+(3x^2-12)=180

We move all terms to the left:

(5x-10)+(3x^2-12)-(180)=0

We get rid of parentheses

3x^2+5x-10-12-180=0

We add all the numbers together, and all the variables

3x^2+5x-202=0

a = 3; b = 5; c = -202;
Δ = b2-4ac
Δ = 52-4·3·(-202)
Δ = 2449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{2449}}{2*3}=\frac{-5-\sqrt{2449}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{2449}}{2*3}=\frac{-5+\sqrt{2449}}{6}
$